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Exercise

$\left(\frac{bh}{2}-\frac{4hb^3}{24b^2}\right)^{-\frac{b}{2}}$

Step-by-step Solution

1

Simplify the fraction $\frac{-4hb^3}{24b^2}$ by $b$

$\left(\frac{bh}{2}+\frac{-4hb}{24}\right)^{\frac{-b}{2}}$
2

Take $\frac{-4}{24}$ out of the fraction

$\left(\frac{bh}{2}-\frac{1}{6}hb\right)^{\frac{-b}{2}}$

Final answer to the exercise

$\left(\frac{bh}{2}-\frac{1}{6}hb\right)^{\frac{-b}{2}}$

Try other ways to solve this exercise

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  • Find the derivative
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  • Factor by completing the square
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Main Topic: Factorization

In mathematics, factorization or factoring is the decomposition of an object (for example, a number, a polynomial, or a matrix) into a product of other objects, or factors, which when multiplied together give the original.

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