$\lim_{x\to3}\left(\frac{-5\cdot\ln\left(x-2\right)}{x-3}\right)$
$-8x-30=-12x-58$
$\left(6p^2+\:2q\right)\:\left(6p^2-\:2q\right)$
$-4g+\left(-2\right)+2g+3$
$\lim_{x\to0}\left(\left(\frac{\left(2^x+6^x\right)}{x}\right)\right)$
$p\left(x\right)=6x^4-18x^3+6x^2-30x+36$
$4a+4a$
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