$\int\frac{x\left(e^2\right)}{2\left(1+x\right)^2}dx$

$64x^8-121y^{12}$

$\left(2gh+3\right)^3$

$-8w-5<-2w+4$

$\int\left(\frac{xln\left(3x^2+1\right)}{3x^2+1}\right)dx$

$\left(\frac{6.00}{5.40}\right)-1.100$

$\left(8x^2+9x^2\right)+\left(7xy^2+10y^2-5\right)$