Starting from the left-hand side (LHS) of the identity
Apply the trigonometric identity: $1+\cot\left(\theta \right)^2$$=\csc\left(\theta \right)^2$, where $x=w$
Since $\sin$ and $\csc$ are opposite functions they cancel when multiplying
Any expression to the power of $1$ is equal to that same expression
Since we have reached the expression of our goal, we have proven the identity
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