$\frac{180x-x^4}{x-6}$
$m-n-4p-3m-2n+4$
$\lim_{x\to\infty}\left(\frac{x^2-4x+6}{x^3-4x^2+13}\right)$
$\frac{dy}{dx}=\frac{-\cos\left(y\right)}{\left(1+e^{-x}\right)\sin\left(y\right)}$
$2sinx\cdot cosx=2sinx$
$5\cos^2x=2\cos x$
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