4v<164v<164v<16
3g+6g3g+6g3g+6g
∫x2+3x2(x+2)dx\int\frac{x^2+3}{x^2\left(x+2\right)}dx∫x2(x+2)x2+3dx
y=2x−1x2y=\frac{2}{x}-\frac{1}{x^{2}}y=x2−x21
limx→2(x2−44x2+5x−6)\lim_{x\to2}\left(\frac{x^2-4}{4x^2+5x-6}\right)x→2lim(4x2+5x−6x2−4)
4x − 3 +5x −12x +84x\:-\:3\:+5x\:-12x\:+84x−3+5x−12x+8
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