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Exercise

$\left(-3a^2bc\right)\:\left(2a^2b^4c\right)$

Step-by-step Solution

1

Multiply $3$ times $-2$

$-6a^2bca^2b^4c$
2

When multiplying exponents with same base we can add the exponents

$-6a^{4}bcb^4c$
3

When multiplying exponents with same base you can add the exponents: $-6a^{4}bcb^4c$

$-6a^{4}b^{5}c\cdot c$
4

When multiplying two powers that have the same base ($c$), you can add the exponents

$-6a^{4}b^{5}c^2$

Final answer to the exercise

$-6a^{4}b^{5}c^2$

Try other ways to solve this exercise

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Similar Questions Solved

$2m^2\cdot2m^3$

$4v^3\cdot vu^2$

$3^2\cdot3^2$

$5^2\cdot5^2$

$\left(-6x^3\right)\left(7x^4\right)$

$\left(x^2\right)\left(x^2\right)$

$4r^{-3}\cdot2r^2$

Main Topic: Multiply powers of same base

When multiplying powers of same base we can add the exponents.

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