$3\left(x+b\right)$
$-2x^4+6x^2-4x$
$\frac{\csc a}{\sin a}-\frac{1}{\tan^2a}=1$
$\frac{d}{dx}\left(3X^4-2X+8\right)$
$\int\frac{7}{2}\sqrt[3]{x^4}dx$
$y'+2.5y=1.6x$
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