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Exercise

$\left(-5x^2-3x\right)-\left(2-4x+6x^2\right)+\left(9x-10\right)$

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Final answer to the exercise

$-11x^2+10x-12$

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$-16x^2-64x\:+55<=0$

$\arctan\left(\tan\left(-\frac{16\pi}{15}\right)\right)$

$\frac{\csc\left(x\right)}{\sin\left(x\right)}+\tan^2\left(x\right)$
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