$( m + 3 ) ^ { 3 }$
$14>v+-2$
$1-x-x^2>0$
$sec\left(x\right)cosec\left(x\right)-cot\left(x\right)=tan\left(x\right)$
$x^2-2x=-16$
$\left(a+4\right)\left(a-4\right)-a^2$
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