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Exercise

$\left(1+\sqrt{2x-5}\right)^2$

Step-by-step Solution

1

Expand the expression $\left(1+\sqrt{2x-5}\right)^2$ using the square of a binomial

$(a+b)^2=a^2+2ab+b^2$
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2

Take the square of the first term: $1$

$1$
3

Twice ($2$) the product of the two terms: $1$ and $\sqrt{2x-5}$

$2\sqrt{2x-5}$
4

Take the square of the second term: $\sqrt{2x-5}$

$2x-5$
5

Add the three results, and we obtain the expanded polynomial

$1+2\sqrt{2x-5}+2x-5$

Final answer to the exercise

$1+2\sqrt{2x-5}+2x-5$

Try other ways to solve this exercise

  • Choose an option
  • Product of Binomials with Common Term
  • FOIL Method
  • Find the integral
  • Find the derivative
  • Factor
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
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Similar Questions Solved

$\left(x+2\right)\left(x+3\right)$

$\left(2+\sqrt{y}\right)\left(2-\sqrt{y}\right)$

$\left(6x-5\right)\left(2x+3\right)$

$4\left(4a+5\right)$

$\left(5x+2y\right)\left(5x-2y\right)$

$\left(2x+6\right)^2$

$\left(x-6\right)\left(x-5\right)$

Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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