Expand the expression $\left(1+\tan\left(x\right)\right)^2$ using the square of a binomial: $(a+b)^2=a^2+2ab+b^2$
Combining like terms $2\tan\left(x\right)$ and $-\tan\left(x\right)$
Applying the trigonometric identity: $1+\tan\left(\theta \right)^2 = \sec\left(\theta \right)^2$
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