$6u+2=9u+14$
$x-19=-14$
$\left(\frac{5^{-4}\cdot5^{-1}}{3^{2}\cdot5^{-3}}\right)^{-\frac{1}{2}\left(\frac{3^{4}\cdot5^{3}}{3^{20}5^{4}}\right)^{-1}}$
$\left(a+3\right)\left(a+1\right)b$
$\left(2x^2y-y^3\right)^2$
$4x+8=2x+16$
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