$3x^2-8x=3$
$\sqrt { 2 x + 5 } - 4 = 3$
$x-2-x+5$
$\int\frac{\left(2x+1\right)}{\left(x^2-6x+13\right)^2}dx$
$\lim_{x\to\infty}\left(\frac{ln\left(8x+7\right)}{ln\left(9x+10\right)+4}\right)$
$\left(2x^2\:-\:y^2\right)^2\:$
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