$x^2-6x+9\ge0$
$\int x\cdot\sqrt[3]{x^2-9}dx$
$1+2\cdot5$
$\left(0.2819740503\right)^{10}-1$
$20+90+51mnuv$
$\frac{\left(4x+3y>52\right)}{\left(x-2y>6\right)}$
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