$\sqrt[32]{1+255\left(16^2+1\right)\left(16^4+1\right)\left(16^8+1\right)}$

$\tan\left(a\right)^2+\cot\left(a\right)^2=\sec\left(a\right)^2+\csc\left(a\right)^2-2$

$\left(2x+3y\right)\left(x+4y\right)^2$

$c^3+4c-4c^3$

$3\cos2x+1$

$\left(-7\right)-\:\left(\:+\:8\:\right)-\:\left(-\:10\right)$

$\left(a^3\right)^6=\left(a^2\right)^x$