2−sec2z=1−tan2z2-sec^2z=1-tan^2z2−sec2z=1−tan2z
(y−5)5\left(y^{-5}\right)^5(y−5)5
3x+4y−z; x=−1; y=−1; z=23x+4y-z;\:x=-1;\:y=-1;\:z=23x+4y−z;x=−1;y=−1;z=2
∫ 2xx2+7x+10dx\int\:\frac{2x}{x^2+7x+10}dx∫x2+7x+102xdx
8−6⋅3+12(2−5)8-6\cdot3+\frac{12}{\left(2-5\right)}8−6⋅3+(2−5)12
(5a−2b)(4a−3c)\left(5a-2b\right)\left(4a-3c\right)(5a−2b)(4a−3c)
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