$\int\frac{6x^2-10}{x^3-5x}dx$
$6m^2\cdot n+10m^2=16m$
$\lim_{x\to\infty}\left(\frac{e^{x+7}-\left(x+8\right)}{\left(x+7\right)^2}\right)$
$16y^2+24y+9$
$-4x+5>20-10x$
$\int\frac{4}{\left(x^2+2x-8\right)}dx$
$8f^4\cdot2f^3$
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