$\:7x-5=65$
$\frac{m^4-4}{m^2+2}$
$\int\frac{2x^2-5x-7}{x-3}dx$
$\frac{\left(1+2v\right)}{\left(v^2+v+1\right)}dv=-\frac{3}{x}dx$
$\frac{\frac{1}{3}m}{4}=\frac{3}{\frac{1}{4}}$
$x^2+13x-30=0$
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