$\left(\frac{1}{6}x-3x\right)$
$\frac{dx}{dy}=\frac{1+2y^2}{y\cos x}$
$\left(3^{-8}\cdot9^3\cdot3^8\cdot9^{-3}\right)-11$
$-12+14+-20+-8+14+80$
$\left(5m+7\right)\left(5m-7\right)$
$4x^2+28x+49=0$
$5x+2y=7$
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