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Exercise

$\left(2x^2a^{+3}+3y^5b^8\right)^2$

Step-by-step Solution

1

Expand the expression $\left(2x^2a^3+3y^5b^8\right)^2$ using the square of a binomial

$(a+b)^2=a^2+2ab+b^2$
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2

Take the square of the first term: $2x^2a^3$

$4x^{4}a^{6}$
3

Twice ($2$) the product of the two terms: $2x^2a^3$ and $3y^5b^8$

$12x^2a^3y^5b^8$
4

Take the square of the second term: $3y^5b^8$

$9y^{10}b^{16}$
5

Add the three results, and we obtain the expanded polynomial

$4x^{4}a^{6}+12x^2a^3y^5b^8+9y^{10}b^{16}$

Final answer to the exercise

$4x^{4}a^{6}+12x^2a^3y^5b^8+9y^{10}b^{16}$

Try other ways to solve this exercise

  • Choose an option
  • Product of Binomials with Common Term
  • FOIL Method
  • Find the integral
  • Find the derivative
  • Factor
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
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Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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