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Exercise

$\left(2x^2y-3y^2x-4cosx\right)\:\left(3t^2\right)\:\left(cos^2t\right)$

Step-by-step Solution

1

Multiply the single term $3t^2\cos\left(t\right)^2$ by each term of the polynomial $\left(2x^2y-3y^2x-4\cos\left(x\right)\right)$

$6x^2yt^2\cos\left(t\right)^2-9y^2xt^2\cos\left(t\right)^2-12t^2\cos\left(x\right)\cos\left(t\right)^2$

Final answer to the exercise

$6x^2yt^2\cos\left(t\right)^2-9y^2xt^2\cos\left(t\right)^2-12t^2\cos\left(x\right)\cos\left(t\right)^2$

Try other ways to solve this exercise

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  • Product of Binomials with Common Term
  • FOIL Method
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  • Find the derivative
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  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
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Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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