Learn how to solve problems step by step online. Solve the differential equation (2x-y^4)dx-4y^3(x+2y^4)dy=0. The differential equation \left(2x-y^4\right)dx-4y^3\left(x+2y^4\right)dy=0 is exact, since it is written in the standard form M(x,y)dx+N(x,y)dy=0, where M(x,y) and N(x,y) are the partial derivatives of a two-variable function f(x,y) and they satisfy the test for exactness: \displaystyle\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}. In other words, their second partial derivatives are equal. The general solution of the differential equation is of the form f(x,y)=C. Using the test for exactness, we check that the differential equation is exact. Integrate M(x,y) with respect to x to get. Now take the partial derivative of x^2-y^4x with respect to y to get.

Solve the differential equation (2x-y^4)dx-4y^3(x+2y^4)dy=0