$4v^2\cdot3vu^4$
$\left(-x^2y\right)-\left(\frac{2}{3}x^m\right)\left(-\frac{3}{4}a^2y^n\right)$
$\left(x-1\right)\left(y'\right)'=y$
$b\left(x^{2}a-6x^{3}a^{2}b-4x^{3}a\right)=x^{2}a$
$\left(\frac{a^{-8}b}{a^{-5}b^3}\right)$
$\left(x^2+u\right)^2$
$x^2-2x-16$
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