$\int u\sin^23vdu$
$\left(\frac{1}{4}x\:+\:\frac{1}{5}\right)\left(\frac{1}{4}x-\frac{5}{3}\right)$
$y\left(x^2+1\right)^3\frac{dy}{dx}=x\left(1-y^2\right)^3$
$81x^2-90x-25$
$2x^5+9x^4+9x^3-x^2-3x$
$54\cdot73$
$2x^2+5x>\:3x-1$
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