3x2−4x+13x^2-4x+13x2−4x+1
1−2sin2(x)=sin2(x)+11-2\sin^2\left(x\right)=\sin^2\left(x\right)+11−2sin2(x)=sin2(x)+1
limx→∞(8arctan2(x))\lim_{x\to\infty}\left(8\arctan^2\left(x\right)\right)x→∞lim(8arctan2(x))
x2+160x+104x^2+160x+10^4x2+160x+104
x+8xx−5=40x−5x+\frac{8x}{x-5}=\frac{40}{x-5}x+x−58x=x−540
dydx=1+x2−xy1+x2\frac{dy}{dx}=\sqrt{1+x^2}-\frac{xy}{1+x^2}dxdy=1+x2−1+x2xy
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