$28\cdot2$
$\int_0^5\left(\frac{1+6x-x^2}{9}\right)dx$
$9\:-\:3x\:\ge\:-15\:-\:6x$
$y=\left(x+7\right)\left(x+5\right)$
$\frac{dy}{dx}=\frac{y^2\ln\left(x\right)}{x}$
$\frac{d^2}{dx^2}\sqrt[3]{2x^3+5}$
$\int 5 ^ { 3 x } d x$
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