$\frac{36m^6n^5}{9m^5n^2}$
$\log\left(x\right)+\log\left(y\right)=\frac{1}{2}\log\left(9y^2\right)$
$costa\:\:no$
$6\left(4a-3\right)$
$48y-18$
$\frac{dy}{dt}=\frac{y}{1+t}-\frac{y}{t}+t^2\left(1+t\right)$
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