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Exercise

$\left(3p^2\right)\cdot\left(7pq^2-6pr\right)$

Step-by-step Solution

1

Multiply the single term $3p^2$ by each term of the polynomial $\left(7pq^2-6pr\right)$

$21pq^2p^2-18prp^2$
2

When multiplying exponents with same base you can add the exponents: $21pq^2p^2$

$21p^{3}q^2-18prp^2$
3

When multiplying exponents with same base you can add the exponents: $-18prp^2$

$21p^{3}q^2-18p^{3}r$

Final answer to the exercise

$21p^{3}q^2-18p^{3}r$

Try other ways to solve this exercise

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  • Product of Binomials with Common Term
  • FOIL Method
  • Find the integral
  • Find the derivative
  • Factor
  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
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$\left(x-6\right)\left(x-5\right)$

Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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