$\sin\left(x\right)=2\sin^2\left(x\right)-1$
$4\cdot\left(-2\right)\cdot\left(+11\right)\cdot\left(+5\right)\cdot\left(-6\right)$
$400n^2-9a^2$
$\left(-x^3+3\right)\left(-2x+5x^{-2}-5\right)$
$\left(3a^2b+16\right)\left(3a^2b+6x\right)$
$\int\frac{\left(x-1\right)}{x^4+6x^3+9x^2}dx$
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