Exercise
$\left(3w^2x^3-2y^5\right)^3$
Step-by-step Solution
Learn how to solve special products problems step by step online. Expand the expression (3w^2x^3-2y^5)^3. The cube of a binomial (difference) is equal to the cube of the first term, minus three times the square of the first by the second, plus three times the first by the square of the second, minus the cube of the second term. In other words: (a-b)^3=a^3-3a^2b+3ab^2-b^3 = (3w^2x^3)^3+3(3w^2x^3)^2(-2y^5)+3(3w^2x^3)(-2y^5)^2+(-2y^5)^3 =. Multiply 3 times -2. Multiply 3 times 3. The power of a product is equal to the product of it's factors raised to the same power.
Expand the expression (3w^2x^3-2y^5)^3
Final answer to the exercise
$27w^{6}x^{9}-54w^{4}y^5x^{6}+9w^2x^3\left(-2y^5\right)^2+\left(-2y^5\right)^3$