$3^x=9^{12}^{+x}$
$6x^2+x-2=0$
$8\log_{64}+3\log_{\frac{1}{27}}-5\log_{625}+\log_{1000}$
$\lim_{x\to0}\left(\frac{x^3-2x^2+1}{3x^2-6x}\right)$
$3x^2-5x-3$
$2\cdot2\cdot3$
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