$\frac{x-2}{4}=-3$
$\frac{2x^3-3x^2-3x+2}{x-2}$
$4x^2-36xy+81y^2$
$5-9x+4+3-5x$
$\lim_{x\to\frac{4}{3}}\left(\frac{2-3x}{x-\frac{4}{3}}\right)$
$q^2-24q+80$
$\int\left(\sqrt[3]{3-4y^2}\left(-8y\right)\right)dx$
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