Exercise
$\left(3x-2\right)^2+\left(2x+3\right)^2-13\left(x+1\right)\left(x-1\right)$
Step-by-step Solution
Learn how to solve problems step by step online. Expand the expression (3x-2)^2+(2x+3)^2-13(x+1)(x-1). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Multiply the single term -13 by each term of the polynomial \left(x^2-1\right). Expand \left(3x-2\right)^2. Add the values 4 and 13.
Expand the expression (3x-2)^2+(2x+3)^2-13(x+1)(x-1)
Final answer to the exercise
$26$