$\left(3b+\frac{1}{3}\right)^2$
$\int\frac{6x+2}{7x^2+2x}dx$
$\frac{d}{dx}\left(\frac{1}{8}\right)ln\left[\frac{1-cos\left(2x\right)}{1+cos\left(2x\right)}\right]$
$1=\theta_{x}\sos+\theta_{z}u_{1}s$
$\cot^2a^2$
$\frac{2x}{x-3}=4$
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