$\frac{x^3-3x^3-2x+1}{x-2}$
$1-\left(0-7\right)+7+\left(-1+2-5\right)$
$\left(3x^3+6xy^2\right)dx+\left(6x^2y+4y^3\right)dy=0$
$\left(3m+\:2v\right)^2$
$12x+6>-4+7x$
$\frac{x^4+2}{x^2+4x+1}$
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