Exercise
$\left(4sin\theta\:+4cos\theta\:\right)^2=16+16sin2\theta\:$
Step-by-step Solution
Learn how to solve problems step by step online. Prove the trigonometric identity (4sin(t)+4cos(t))^2=16+16sin(2t). Starting from the left-hand side (LHS) of the identity. Factor the polynomial \left(4\sin\left(\theta\right)+4\cos\left(\theta\right)\right) by it's greatest common factor (GCF): 4. The power of a product is equal to the product of it's factors raised to the same power. Expand the expression \left(\sin\left(\theta\right)+\cos\left(\theta\right)\right)^2 using the square of a binomial: (a+b)^2=a^2+2ab+b^2.
Prove the trigonometric identity (4sin(t)+4cos(t))^2=16+16sin(2t)
Final answer to the exercise
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