$m\left(x\right)=\left(x^2+2\right)^4\left(x^3+2\right)^3$

$\int_{-3}^2\left(\frac{1}{\left(x+2\right)^{\frac{4}{3}}}\right)dx$

$\left(1-x\right)+\left(x-1\right)$

$\left(-9x+9\right)$

$\frac{2x^2+8x+6}{2x+2}$

$x^2-10x-171=0$

$x^2-3x+36$