$\left(\frac{2}{3}a+5b\right)^2$
$\left(-2\right)\left(-7\right)4+\left(-18\right)$
$\left(-3\right)\left(-4\right)\left(-4\right)$
$\left(2a^6+6a^3\right)^2$
$36a^2\:-12a\:+1$
$\frac{64x^6-125}{4x^2-5}$
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