$\frac{2x^3+6x^2-x-3}{x^3+3x^2+x-3}$
$y'=e^{x+y},y\left(0\right)=0$
$4x+4y^3-5+6-2y^3-5y^3+5x$
$\frac{d}{dx}\left(x+9\right)^4\left(5x-6\right)^3$
$3\cdot5-2+1$
$x+10x$
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