$dy\left(3x+3y-4\right)=\left(-x-y\right)dx$
$\frac{dy}{dx}=\frac{5x^2}{4y}\:$
$k1^4+1^3-11\left(1\right)^4+11\cdot1-3$
$18x^312x^2-15x$
$\tan\left(45+\frac{x}{2}\right)=\frac{\cos\left(x\right)}{1-\sin\left(x\right)}$
$\int\left(\frac{\arcsin\left(\frac{x}{7}\right)^2}{\sqrt{49-x^2}}\right)dx$
$\left(6^4.\:2\right)^3$
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