$\int\frac{2x}{x^2-6x+5}dx$
$-2\left(7-3\right)$
$\lim_{x\to\frac{1}{2}}\left(\frac{4-32x^3}{1-4x^2}\right)$
$5x+8<2x-6$
$4x-3^2$
$x+7<5-2x$
$\left(y-x\right)y^{'\:}=y-x+8$
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