$\sqrt[3]{4x^2y}\:\sqrt[3]{2x^5y^2}$

$-32x^2+48xy-18y^2$

$\lim_{x\to\infty}\left(\frac{x-4}{x^2+4x+3}\right)$

$\frac{d}{dy}=\frac{3x+1}{2-4x}$

$\frac{\sin^2\left(x\right)}{-\sin\left(x\right)}$

$\lim_{t\to\infty}\left(\frac{10t}{t^2+1}\right)$

$-9x^3y^2\left(-13x^2y^5\right)$