$\frac{2x-3}{x+5}\le1$

$\lim_{x\to0}\left(\frac{sinx}{\pi-x}\right)$

$\left(\frac{3}{4}b^2-\frac{6x^3}{5}\right)\left(\frac{6b^3}{5}+\frac{3x^3}{4}\right)$

$\left(3x^2-2x+1\right)+\left(-x^2+3x+1\right)$

$3-3\cdot2$

$\left(x^2-6y^2\right)\left(x^2+4y^2\right)$