$\frac{x^6-4x^3+4}{x^3-4x^2}$
$y=x^5\cdot x^4$
$\int\frac{5sin^{-1}\left(x\right)}{x^2}dx$
$\sin\left(x-\frac{\pi}{4}\right)=-cos\left(x+\frac{\pi}{4}\right)$
$\int\left(\frac{e^{-2x}}{-2}\right)dx$
$\:\left(y^6+3x\right)^2$
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