Exercise
$\left(6a^{n+2}+4b^{m-1}\right)\left(6a^{n+2}-4b^{m-1}\right)$
Step-by-step Solution
Learn how to solve problems step by step online. Simplify the product of conjugate binomials (6a^(n+2)+4b^(m-1))(6a^(n+2)-4b^(m-1)). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. The power of a product is equal to the product of it's factors raised to the same power. Multiply -1 times 16. Multiply the single term 2 by each term of the polynomial \left(n+2\right).
Simplify the product of conjugate binomials (6a^(n+2)+4b^(m-1))(6a^(n+2)-4b^(m-1))
Final answer to the exercise
$36a^{\left(2n+4\right)}-16b^{\left(2m-2\right)}$