$\lim_{x\to6}\left(\frac{x\left(\sqrt{x+3}-3\right)}{x-6}\right)$
$Y=\frac{\sin\left(2x\right)^2}{1-\sin^2\left(x\right)}$
$15\:-\:\left(-20\right)$
$x3^2$
$-4\left(4-2+5\right)-1-1-\left|8+\left(-3-1\right)-\left(-7+4\right)\right|+3-4$
$5y+8y+4z$
$2\left(-3g\right)$
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