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f(x)=(8+12sin(x)6sin(x)^2sin(x)^3)cos(x)−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

(8+12sin⁡(x)+6sin⁡(x)2+sin⁡(x)3)cos⁡(x)\left(8+12\sin\left(x\right)+6\sin\left(x\right)^2+\sin\left(x\right)^3\right)\cos\left(x\right)

Step-by-step Solution

1

Multiply the single term cos⁡(x)\cos\left(x\right) by each term of the polynomial (8+12sin⁡(x)+6sin⁡(x)2+sin⁡(x)3)\left(8+12\sin\left(x\right)+6\sin\left(x\right)^2+\sin\left(x\right)^3\right)

8cos⁡(x)+12sin⁡(x)cos⁡(x)+6sin⁡(x)2cos⁡(x)+sin⁡(x)3cos⁡(x)8\cos\left(x\right)+12\sin\left(x\right)\cos\left(x\right)+6\sin\left(x\right)^2\cos\left(x\right)+\sin\left(x\right)^3\cos\left(x\right)

Final answer to the exercise

8cos⁡(x)+12sin⁡(x)cos⁡(x)+6sin⁡(x)2cos⁡(x)+sin⁡(x)3cos⁡(x)8\cos\left(x\right)+12\sin\left(x\right)\cos\left(x\right)+6\sin\left(x\right)^2\cos\left(x\right)+\sin\left(x\right)^3\cos\left(x\right)

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(8+12sin(x)+6sin(x)2+sin(x)3)cos(x)
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