$\lim_{x\to-\infty}\left(8\right)$
$\frac{2-6x}{x+3}$
$1,66666\:+\:2,5\:-0,16666$
$\lim_{x\to2}\left(5^x+2^x+4\right)$
$6 y ^ { 2 } + 5 y = 0$
$\left(x^4+2y^4\right)^2$
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