$\int_{-1}^2\left(x^2-4x\right)dx$
$\frac{dy}{dx}=\frac{1}{\left(2y+1\right)}$
$2x^2-15x+25$
$16-104x^2+166x^2$
$\lim_{h\to0}\left(\frac{\left(\frac{1}{1-x}+h\right)-\frac{1}{1-x}}{h}\right)$
$-x^2+2x+1=0$
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